-3[2(x+4y)-(x-4)]=1

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Solution for -3[2(x+4y)-(x-4)]=1 equation:


Simplifying
-3[2(x + 4y) + -1(x + -4)] = 1
-3[(x * 2 + 4y * 2) + -1(x + -4)] = 1
-3[(2x + 8y) + -1(x + -4)] = 1

Reorder the terms:
-3[2x + 8y + -1(-4 + x)] = 1
-3[2x + 8y + (-4 * -1 + x * -1)] = 1
-3[2x + 8y + (4 + -1x)] = 1

Reorder the terms:
-3[4 + 2x + -1x + 8y] = 1

Combine like terms: 2x + -1x = 1x
-3[4 + 1x + 8y] = 1
[4 * -3 + 1x * -3 + 8y * -3] = 1
[-12 + -3x + -24y] = 1

Solving
-12 + -3x + -24y = 1

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '12' to each side of the equation.
-12 + -3x + 12 + -24y = 1 + 12

Reorder the terms:
-12 + 12 + -3x + -24y = 1 + 12

Combine like terms: -12 + 12 = 0
0 + -3x + -24y = 1 + 12
-3x + -24y = 1 + 12

Combine like terms: 1 + 12 = 13
-3x + -24y = 13

Add '24y' to each side of the equation.
-3x + -24y + 24y = 13 + 24y

Combine like terms: -24y + 24y = 0
-3x + 0 = 13 + 24y
-3x = 13 + 24y

Divide each side by '-3'.
x = -4.333333333 + -8y

Simplifying
x = -4.333333333 + -8y

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